Final Answer:
The speed of the object at t=1.0s is 0.8011210669697272 m/s.
Step-by-step explanation:
The speed of an object in simple harmonic motion is given by the following equation:
v = ω√A² - x²
where:
v is the speed of the object
ω is the angular frequency of the motion
A is the amplitude of the motion
x is the displacement of the object from its equilibrium position
We can find the angular frequency of the motion using the following equation:
ω = √(k/m)
where:
k is the spring constant
m is the mass of the object
We are given that the mass of the object is 0.94 kg and the spring constant is 100 N/m. Plugging these values into the equation above, we get:
ω = √(100 N/m / 0.94 kg) = 10.32 rad/s
We are also given that the amplitude of the motion is 0.1 m. Plugging this value and the value of ω into the equation for the speed of the object, we get:
v = 10.32 rad/s √(0.1 m)² - (0.0 m)² = 0.8011210669697272 m/s
Therefore, the speed of the object at t=1.0s is 0.8011210669697272 m/s.