Final answer:
The volume of the oxygen gas sample at STP is 1.34 liters.
Step-by-step explanation:
To determine the volume of oxygen gas at STP, we can use the ideal gas law equation: PV = nRT. First, we need to convert the mass of oxygen gas to moles using the molar mass of oxygen. Oxygen has a molar mass of 32 g/mol. So, 1.76 g of oxygen is equal to 1.76/32 = 0.055 moles.
At STP (standard temperature and pressure), the temperature is 273 K and the pressure is 1 atm. R is the ideal gas constant, which is equal to 0.0821 L.atm/mol.K. Plugging in the values into the ideal gas law equation, we get:
(1 atm) * V = (0.055 mol) * (0.0821 L.atm/mol.K) * (273 K)
V = (0.055 mol) * (0.0821 L.atm/mol.K) * (273 K) / (1 atm)
V = 1.34 L
Therefore, the volume of the oxygen gas sample is 1.34 liters.