Question

Please helppppppppppppp

A net force of 15N acts upon a body of mass 3kg for 5s, calculate the change in the speed of the body​

Answer 1

• Force, F = 15 N
• Mass,m = 3 kg
• Time taken, t = 5 sec
• (v-u) =?

As we know –

`\qquad`
`\purple{\bf \twoheadrightarrow F = m a }`

`\qquad`
`\bf \twoheadrightarrow F = m ( v-u)/(t)`

`\qquad`
`\sf \twoheadrightarrow 15 = 3 * (v-u)/(5)`

`\qquad`
`\sf \twoheadrightarrow 3 * (v-u)/(5) = 15`

`\qquad`
`\sf \twoheadrightarrow (3)/(5) * (v-u) = 15`

`\qquad`
`\sf \twoheadrightarrow (v-u)= 15 * (5)/(3)`

`\qquad`
`\sf \twoheadrightarrow (v-u)= \cancel{15} * \frac{5}{\cancel{3}}`

`\qquad`
`\sf \twoheadrightarrow v-u = 5 * 5`

`\qquad`
`\purple{\bf \twoheadrightarrow v-u = 25 }`

• Henceforth, the change in the speed of the body is 25 m/s.