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Write the equation of a line that passes through the point (-16,-14) with a slope of -7/8 using the point-slope form?

User Moscas
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Final answer:

The equation of the line that passes through the point (-16,-14) with a slope of -7/8 is y = (-7/8)x - 21/4.

Step-by-step explanation:

To find the equation of a line in point-slope form, you can use the formula: y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. In this case, the point is (-16, -14) and the slope is -7/8. Substituting these values into the formula, we have: y - (-14) = (-7/8)(x - (-16)).

Simplifying this equation, we get: y + 14 = (-7/8)(x + 16). Finally, we can rewrite this equation in slope-intercept form (y = mx + b) by simplifying further: y = (-7/8)x + 7/4 - 14. Thus, the equation of the line is y = (-7/8)x - 21/4.

User Wmatt
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