Question

A 16 kg block is dragged over a rough, horizontal surface by a constant force of 143 N acting at an angle of 29.1�� above the horizontal. The block is displaced 64.1 m, and the coefficient of kinetic friction is 0.127. What is the work done by the applied force on the block?

1) 0 J
2) 920 J
3) 1,040 J
4) 1,160 J

Answer 1

The work done by the applied force on the block is approximately 1,040 J.

Step-by-step explanation:

The work done by the applied force on the block can be calculated using the formula:

Work = Force * Distance * cosθ

Where:

• Force is the magnitude of the applied force (143 N)
• Distance is the displacement of the block (64.1 m)
• θ is the angle between the force and the displacement (29.1°)

Substituting the given values, we get:

Work = 143 N * 64.1 m * cos(29.1°)

Calculating this expression, the work done by the applied force on the block is approximately 1,040 J.