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A young girl with mass 44.0 kg is sliding on a horizontal, frictionless surface with an initial momentum that is due east and that has magnitude 85.0 kg ��� m/s. Starting at 0 s, a net force with magnitude f = (8.35 N/s)t and direction due west is applied to the girl. What is the magnitude of the girl's momentum at t = 5 s?

1) 42.0 kg ��� m/s
2) 43.5 kg ��� m/s
3) 45.0 kg ��� m/s
4) 46.5 kg ��� m/s

User MRAB
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1 Answer

5 votes

Final answer:

Using the given force function, we calculate the impulse and determine the magnitude of the girl's final momentum to be 19.375 kg · m/s, not matching the provided answer choices. This suggests there is an error in the question details or the answer options.

Step-by-step explanation:

To determine the magnitude of the girl's momentum at t = 5 s, we'll need to calculate the change in momentum caused by the net force over that period. The initial momentum of the girl is 85.0 kg · m/s eastwards. The net force applied to the girl has a magnitude that changes over time, defined as f = (8.35 N/s)t, directed due west, opposing her initial momentum. The impulse experienced by the girl due to the force is the integral of the force over the time interval (0 to 5 s). The impulse is equal to the change in momentum (Δp).

Impulse = ∫ F dt = ∫ (8.35t) dt from 0 to 5 s = ½ * 8.35 * 5² = 104.375 N · s. This impulse has been applied in the direction opposite to the girl's initial momentum.

The resulting momentum at t = 5 s is: p_final = p_initial - Impulse = 85.0 kg · m/s - 104.375 kg · m/s = -19.375 kg · m/s (due west). Since the question asks for the magnitude, we simply take the absolute value: |p_final| = 19.375 kg · m/s, which is not an answer choice provided. Hence, there seems to be an error either in the question details or the answer options.

User Chrisvillanueva
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