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Many nuclear division without cytokinesis will result in formation

A) meiosis
B) schizogony
C) mitosis
D) conjugation
E) crossing over

User Asaph
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Final answer:

The multiple nuclear divisions without cytokinesis result in schizogony, distinct from mitosis and meiosis which are usually followed by cytokinesis and yield genetically different outcomes.

Step-by-step explanation:

Many nuclear divisions without cytokinesis will result in the formation of schizogony .

Schizogony is a process found in some protozoans, like those responsible for malaria, where the nucleus divides multiple times before the cell itself divides. Contrastingly, both mitosis and meiosis are nuclear division processes in eukaryotic cells that typically result in cytokinesis, the division of the cell's cytoplasm, producing distinct new cells. In mitosis, the end result is two genetically identical cells with the same number of chromosome sets as the original. Meiosis, on the other hand, leads to four unique haploid cells, having half the chromosome sets of the original cell. This is due to one round of DNA replication followed by two rounds of nuclear division, including processes such as crossover and recombination that increase genetic diversity. Neither mitosis nor meiosis naturally involves many nuclear divisions without ensuing cytokinesis. Therefore, schizogony is the correct answer, as it describes the specific case of multiple nuclear divisions without the cytoplasm being divided until later stages.

Mitosis is a single nuclear division that results in two nuclei that are usually partitioned into two new cells. The nuclei resulting from a mitotic division are genetically identical to the original nucleus, with the same number of sets of chromosomes. Meiosis, on the other hand, consists of two nuclear divisions resulting in four nuclei that are usually partitioned into four new cells. The nuclei resulting from meiosis are not genetically identical and contain only one chromosome set.

User JonnyLitt
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