Question

Claire’s mom is 4 years older than twice Claire’s age. The sum of their ages is 58 years. Claire’s age is ___ years, and her mothers age is ____ years

Answer 1

The sum of their ages is 58. The "sum of their ages" includes:

Claire's age + 2(Claire's Gage) + 4 = 58

3(Claire's age) + 4 = 58

3 x Claire's age = 58 -4 = 54

Claire's age= 54/3 = 18

Claire is 18 years old.

Since Claire's mom is 4 years older than twice clears age, her age is (18 x 2) + 4 = 40

So Claire is 18 and her mother is 40

I hope this helps!

Answer 2

Claire is 18 years old and her mother is 40 years old.

Answer with explanation:

Let Claire's age = x years

Age of Claire's mother =(2 x +4 ) years

Sum of the ages of Claire and her mother =58 years

If we write the above statement in terms of equation , it will be

⇒ x + 2 x +4=58

⇒3 x +4=58

⇒3 x =58 -4

⇒3 x =54

Dividing both side by , 3 , we get

→x=18

Claire's age = 18 years

Age of Claire's mother =(2 x +4 )=2×18+4=36+4= 40 years