Question

How many grams of AgNO₃ are needed to make 250.0mL of a solution that is 0.135M?

A) 5.73g
B) 0.174g
C) 9.17g
D) 0.0917g

Answer 1

To make a 0.135M solution with 250.0mL, we need 5.73g of AgNO₃.

Step-by-step explanation:

To calculate the number of grams of AgNO₃ needed to make a 0.135M solution, we need to use the formula:

Molarity (M) = moles of solute / liters of solution

First, we need to convert the volume of the solution to liters:

250.0 mL = 0.250 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x liters of solution

moles of solute = 0.135 mol/L x 0.250 L

moles of solute = 0.03375 mol

Finally, we can convert moles of solute to grams of AgNO₃ using its molar mass:

molar mass of AgNO₃ = 169.87 g/mol

grams of AgNO₃ = moles of solute x molar mass of AgNO₃

grams of AgNO₃ = 0.03375 mol x 169.87 g/mol

grams of AgNO₃ = 5.73 g

So, the correct answer is A) 5.73g.