Question

A 2.8 kg grinding wheel is in the form of a solid cylinder of radius 0.1 m. What constant torque will bring it from rest to an angular velocity of 120 rad/s in 2.5 s.

Answer 1

The constant torque required to bring the grinding wheel from rest to an angular velocity of 120 rad/s in 2.5 s is 416.8 N·m.

Step-by-step explanation:

To find the constant torque required to bring the grinding wheel from rest to an angular velocity of 120 rad/s in 2.5 s, we will use the equation:

Torque = (Moment of inertia) * (Angular acceleration)

The moment of inertia of the grinding wheel can be calculated using the formula for the moment of inertia of a solid cylinder:

Moment of inertia = (1/2) * (Mass) * (Radius^2)

Substituting the given values into the equations and calculating, we find that the constant torque required is 416.8 N·m.