Question

Consider 636 nm light falling on a single slit of width 18 μm. Randomized variables λ = 636 nm w = 18 μm show answer no attempt 50% part (a) find the angle, in degrees, of the third diffraction minimum for the light.

Answer 1

To find the angle of the third diffraction minimum, use the formula sin(θ) = (m * λ) / w. Plugging in the values, the angle is approximately 27.99°.

Step-by-step explanation:

To find the angle of the third diffraction minimum, we can use the formula:

sin(θ) = (m * λ) / w

Where θ is the angle, m is the order of the minimum (in this case, the third minimum, so m = 3), λ is the wavelength of the light (636 nm), and w is the width of the slit (18 μm).

By plugging in the values, we get:

sin(θ) = (3 * 636 nm) / 18 μm

θ ≈ 27.99°

Therefore, the angle of the third diffraction minimum for the light is approximately 27.99°.