Final answer:
The energy of a photon of electromagnetic radiation at a wavelength of 488.0 nm is calculated using the equation E = hc / λ. After converting the wavelength to meters and applying the constants for Planck's constant and the speed of light, the energy is found to be 4.08 × 10-19 J.
Step-by-step explanation:
To calculate the energy of a photon of electromagnetic radiation with a given wavelength, you can use the equation:
E = hc / λ
Where:
E is the energy of the photon in joules (J)
h is Planck's constant (6.626 × 10-34 J·s)
c is the speed of light in a vacuum (3.00 × 108 m/s)
λ is the wavelength of the photon in meters (m)
First, we need to convert the given wavelength from nanometers to meters:
488.0 nm = 488.0 × 10-9 m
Then, we use the equation to find the energy:
E = (6.626 × 10-34 J·s) (3.00 × 108 m/s) / (488.0 × 10-9 m)
E = (6.626 × 10-34 × 3.00 × 108) / 488.0 × 10-9
E = 4.08 × 10-19 J
So, the correct answer is:
a) 4.08 × 10-19 J