Final answer:
To find the area of triangle BDM, additional info is needed. However, with provided base and height measurements, one can use the area formula (1/2 × base × height) to calculate the area in square meters, ensuring the answer has the correct significant figures.
Step-by-step explanation:
To calculate the area of triangle BDM from an isosceles trapezoid ABCD with bases AD = 17 cm, BC = 5 cm, and side AB = 10 cm, where line BM bisects the diagonal AC, we need additional information that is not provided in the question to determine the height of triangle BDM relative to base BM. However, when calculating the area of a triangle with given base and height, the formula is:
Area = 1/2 × base × height
As an example, for a triangle with a base of 166 mm and a height of 930.0 mm, we would calculate the area as follows:
Area = 1/2 × 166 mm × 930.0 mm = 77,190 mm²
Since there is an expectation for the area in square meters and we have our values in square millimeters, we must convert from mm² to m²:
1 mm² = 1e-6 m²
Therefore, the area in square meters is:
Area = 77,190 mm² × 1e-6 m²/mm² = 0.077190 m²
To express this to the proper number of significant figures, considering our initial measurements were to three significant figures (166 mm, 930.0 mm), our area should also be to three significant figures:
Area = 0.0772 m²