Question

____ Al + ____ Cr2O3  ____ Al2O3 + ____ Cr

If the reaction of 23.3 grams of Cr2O3 produces 5.35 grams
of Al2O3, what is the percent yield?

Answer 1

`Y=34.3\%`

Step-by-step explanation:

Hello there!

In this case, according to the balanced chemical reaction:

`2Al + Cr_2O_3 \rightarrow Al_2O_3 + 2Cr`

We notice there is a 1:1 mole ratio between Al2O3 and Cr2O3; thus, the following stoichiometric setup is used to compute the theoretical yield first:

`m_(Al_2O_3 )=23.3gCr_2O_3*(1molCr_2O_3)/(151.99gCr_2O_3) *(1molAl_2O_3)/(1molCr_2O_3) *(101.96gAl_2O_3)/(1molAl_2O_3) \\\\m_(Al_2O_3)=15.6gAl_2O_3`

Thus, the percent yield turns out:

`Y=(5.35g)/(15.6g) *100\%\\\\Y=34.3\%`

Best regards!