Question

A toy car of mass 120 g does vertical loops of radius 20 cm in a track. When the car is in one of these loops at the 45° position shown, its speed is 6 m/s. At that moment, what force does the car exert on the track?

a) 7.2 N
b) 6 N
c) 9.6 N
d) 4.8 N

Answer 1

The force exerted by the car on the track at the 45° position in the vertical loop is 9.6 N.

Step-by-step explanation:

When a toy car of mass 120 g is in a vertical loop, it experiences a centripetal force that keeps it moving in a circular path. At the 45° position, the car's speed is 6 m/s. The force that the car exerts on the track can be determined using the equation F = m * (v^2 / r), where F is the force, m is the mass of the car, v is the velocity, and r is the radius of the loop. Plugging in the values, the force exerted by the car on the track is:

F = 0.120 kg * ((6 m/s)^2 / 0.20 m) = 9.6 N

Therefore, the correct answer is c) 9.6 N.