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The smaller of two consecutive even numbers is seventy-four less than the product of the larger number and ten. Find the numbers? ​

User Erinbrown
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Final answer:

To solve the problem, we set up an equation where the smaller consecutive even number is expressed as the product of the larger number and ten, minus seventy-four. After simplifying the equation, we find that the two consecutive even numbers are 6 and 8.

Step-by-step explanation:

The student asked to find two consecutive even numbers where the smaller number is seventy-four less than the product of the larger number and ten. We can start by defining the larger even number as x, which makes the smaller even number x-2, as they are consecutive even numbers. The problem gives us the equation x-2 = 10x - 74. Simplifying this equation:

  • Move all terms involving x to one side: x - 10x = -74 + 2
  • Combine like terms: -9x = -72
  • Divide by -9 to find x: x = 8

Since x is the larger number, the two consecutive even numbers are 6 and 8.

User JLZenor
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