Question

F varies jointly as q1 and q2 and inversely as the square of d. If F=8 when q1=10, q2=5, and d=5, find F when q1=3, q2=9, and d=3

Answer 1

F varies jointly as q1 and q2 and inversely as the square of d. When q1=3, q2=9, and d=3, the value of F is 18.

Step-by-step explanation:

We are given that F varies jointly as q1 and q2 and inversely as the square of d. This can be written as F = k * (q1 * q2) / (d^2), where k is the constant of variation.

To find the value of k, we can use the given values. When F=8, q1=10, q2=5, and d=5, we have 8 = k * (10 * 5) / (5^2). Solving this equation, we find k = 2.

Now, we can use the value of k to find F when q1=3, q2=9, and d=3. Plugging these values into the equation, we have F = 2 * (3 * 9) / (3^2). Simplifying further, we find F = 18.