Answer:
x=10
Explanation:
Multiply the numbers
2⋅3x=[12(4x+20)]⋅22⋅3=[12(4+20)]⋅2
6x=[12(4x+20)]⋅26=[12(4+20)]⋅2
Combine multiplied terms into a single fraction
6x=[12(4x+20)]⋅26=[12(4+20)]⋅2
6x=[1(4x+20)2]⋅26=⎣⎡1(4+20)2⎦⎤⋅2
Multiply by 1
6x=[1(4x+20)2]⋅26=⎣⎡1(4+20)2⎦⎤⋅2
6x=[4x+20/2]⋅26=[4+20/2]⋅2
Re-order terms so constants are on the left
6x=4x+20/2⋅26=4+20/2⋅2
6x=2⋅4x+20/2
Cancel multiplied terms that are in the denominator
6x=2⋅4x+20/2
6x=4x+20
Subtract 4x from both sides
6x=4x+20
6−4=4+20−4
Simplify
6x-4x=4x+20-4x
2x=4x+20-4x
Combine like terms
2x=20
Divide both sides by the same factor
2x=20
2x/2=20/2
cancel 2 on both sides
20 divided by 2 is 10
so therefore,
x=10