Final answer:
The current drawn by an 1800-W toaster, a 1400-W frying pan, and a 75-W lamp are 15 A, 11.67 A, and 0.625 A, respectively. The total current exceeds the 15-A fuse rating, so this combination will blow the fuse.
Step-by-step explanation:
The question at hand involves calculating the current drawn by each electrical device and determining whether the combined current will blow the 15-A fuse when an 1800-W toaster, a 1400-W electric frying pan, and a 75-W lamp are plugged into a 120-V circuit.
- First, to find the current drawn by each device, you use the formula I = P / V, where I is current, P is power, and V is voltage.
- For the toaster, I = 1800 W / 120 V = 15 A.
- For the frying pan, I = 1400 W / 120 V = 11.67 A.
- For the lamp, I = 75 W / 120 V = 0.625 A.
- Adding up the currents gives us a total of 15 A + 11.67 A + 0.625 A = 27.295 A.
- Since 27.295 A is greater than the 15-A rating of the fuse, this combination of devices will indeed blow the fuse.