Final answer:
A photon at 99.5 MHz is part of the radio waves within the electromagnetic spectrum, which is characterized by lower frequencies and longer wavelengths compared to other parts of the spectrum like visible light.
Step-by-step explanation:
A photon of electromagnetic radiation at 99.5 MHz falls within the radio waves portion of the electromagnetic spectrum. The electromagnetic spectrum is arranged by frequency and wavelength, with radio waves being at the low-frequency, long-wavelength end, followed by microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays as frequency increases and wavelength decreases. Radio waves have much longer wavelengths and lower frequencies compared to visible light which has a much smaller portion of the electromagnetic spectrum. For example, visible light ranges from approximately 380 to 740 nanometers. The energy of a photon is inversely proportional to its wavelength; thus, radio waves have lower energy photons compared to other parts of the spectrum such as visible light or X-rays.