Question

How many milliliters of 0.325 M

NaOH
solution is needed to completely hydrolyze (saponify) 2.70 g
of ethyl octanoate?

Answer 1

To completely hydrolyze 2.70 g of ethyl octanoate, you will need 26.43 mL of 0.325 M NaOH solution.

Step-by-step explanation:

To determine the volume of 0.325 M NaOH solution needed to completely hydrolyze 2.70 g of ethyl octanoate, we first need to write a balanced chemical equation for the reaction. Ethyl octanoate reacts with NaOH to produce sodium octanoate and ethanol. The balanced equation is:

C8H16O2 + NaOH → C8H16O2Na + C2H5OH

Next, we can use the stoichiometry of the reaction and the molarity of NaOH to calculate the volume needed. First, convert the mass of ethyl octanoate to moles using its molar mass.

Then, use the mole ratio from the balanced equation to find the moles of NaOH required. Finally, use the molarity of NaOH to calculate the volume:

2.70 g ethyl octanoate * (1 mol ethyl octanoate/144.22 g ethyl octanoate) * (1 mol NaOH/1 mol ethyl octanoate) * (1000 mL/0.325 mol NaOH) = 26.43 mL of 0.325 M NaOH