Answer:
Step-by-step explanation:
Each chair having mass of 250 kg , separated by 20 m
Total no of chair = 1000 / 20 = 50
Total mass of all chair = 50 x 250 = 12500 kg
Force required to move the chair = mg sinФ where Ф is inclination of lift .
SinФ = 200 / 1000 = .2
Ф = 11.536⁰
Force required to move the chair = mg sin11.53
= 12500 x 9.8 x sin11.53
F = 24485.42 N
velocity of lift = 10 x 1000 / (60 x 60 ) m /s
v = 2.78 m /s
Power required = F v where v is velocity of movement of lift
= 24485.42 x 2.78 W
= 68069.46 W.