Final answer:
The shift-reduce parser derivation stack for the input string 'n+n×n' is E.
Step-by-step explanation:
The given grammar is:
- E → E + T | T
- T → T * F | F
- F → (E) | n
The input string is 'n+n×n', and we need to draw the shift-reduce parser derivation stack.
- Initially, the stack contains only the start symbol E.
- Shift the first symbol 'n' to the stack.
- The stack now contains 'n', so we reduce it to F.
- Shift the next symbol '+' to the stack.
- Shift the next symbol 'n' to the stack.
- The stack now contains F + n, so we reduce it to T.
- Shift the next symbol '×' to the stack.
- Shift the next symbol 'n' to the stack.
- The stack now contains T × n, so we reduce it to T.
- The stack now contains T + T × n, so we reduce it to E.
- The stack now contains E, which is the final reduced form.
Therefore, the shift-reduce parser derivation stack for the input string 'n+n×n' is E.