To solve this system of equations, we can use the method of substitution. Let 'a' represent the price per adult ticket, and 's' represent the price per student ticket. By substituting the value of 'a' in terms of 's' into the second equation and solving, we find that the price per adult ticket is $4.64 and the price per student ticket is $2.16.
To solve this system of equations, we can use the method of substitution. Let's assign variables to the unknowns:
Let 'a' represent the price per adult ticket, and 's' represent the price per student ticket.
From the given information, we can set up the following equations:
125a + 65s = 1200
140a + 50s = 1230
We can solve the first equation for 'a' in terms of 's' and substitute it into the second equation:
125a + 65s = 1200 => a = (1200 - 65s) / 125
Substituting the value of 'a' into the second equation:
140((1200 - 65s) / 125) + 50s = 1230
Simplifying the equation gives:
(168000 - 9100s + 2500s) / 125 = 1230
(168000 - 6600s) / 125 = 1230
Multiplying both sides by 125:
168000 - 6600s = 153750
6600s = 14250
s = 2.16
Substituting this value of 's' back into the equation for 'a' gives:
a = (1200 - 65(2.16)) / 125
a = 4.64
Therefore, the price per adult ticket is $4.64 and the price per student ticket is $2.16.