Question

Two years ago, Jernie was three times as old as his sisfer, cecile. in 4 years, he will be only twice his sister's oge. Find their present ages.

Answer 1

By solving the system of equations, it can be determined that Jernie's current age is 20 years and Cecile's current age is 8 years.

Step-by-step explanation:

Let's denote Jernie's age two years ago as J and Cecile's age two years ago as C. Based on the information provided, we can set up the following equations:

• J = 3C (Two years ago, Jernie was three times as old as Cecile)
• J + 6 = 2(C + 6) (In 4 years, he will be only twice his sister's age)

To find their present ages, we need to solve this system of equations. We start by substituting the first equation into the second equation, giving us 3C + 6 = 2(C + 6). Simplify this to get 3C + 6 = 2C + 12, which reduces to C = 6. Now that we know Cecile's age two years ago, we plug it into the first equation to find Jernie's age two years ago, which is J = 3(6) = 18. Therefore, Jernie's current age is 18 + 2 = 20 and Cecile's current age is 6 + 2 = 8.