Final answer:
100 grams of O2 at STP would occupy 70.0 liters, calculated by determining that the number of moles of oxygen is 3.125 and multiplying by the molar volume at STP, which is 22.4 L/mole.
Step-by-step explanation:
To calculate the volume of 100 grams of O2 at STP (Standard Temperature and Pressure), we start by determining the number of moles of oxygen present. The molar mass of oxygen (O2) is approximately 32 g/mol, which means that 100 grams of O2 is equivalent to 100 g / 32 g/mol = 3.125 moles.
At STP, one mole of any gas occupies 22.4 liters.
Therefore, the volume occupied by 3.125 moles of oxygen is:
3.125 moles × 22.4 L/mole = 70.0 liters.
Hence, 100 grams of oxygen at STP would occupy 70.0 liters.