Question

2. When 47.5 J of heat are added to 13.2 g of a liquid, its temperature rises by 1.72 °C. What i

the heat capacity of the liquid?

Answer 1

Below

Step-by-step explanation:

specific heat cap = j / (gm c)

= 47.5 / (13.2 *1.72) = 2.09 j / (gm-c) or = 2093 j/(kg-C)

Heat capacity = 47.5 / 1.72 = 27.6 J / C

Answer 2

answer : 2.02 J/g°C