Question

If ( B=-q-1 ) and ( C=q-8 ), find an expression that equals ( 3 B+3 C ) in standard form.

Answer 1

After substituting the given expressions for B and C and multiplying them by 3, the q terms cancel out, leaving a constant expression of -27.

Step-by-step explanation:

To find an expression that equals (3B + 3C), we first substitute the given expressions for B and C into the equation. That is:

• B = -q - 1
• C = q - 8

Now, let's multiply both B and C by 3.

3B = 3(-q - 1) = -3q - 3

3C = 3(q - 8) = 3q - 24

When we add these two results together, the q terms will cancel each other out:

3B + 3C = (-3q - 3) + (3q - 24)

The 3q from 3C and the -3q from 3B add up to zero, leaving us with:

3B + 3C = -3 - 24

Adding together the constants gives us:

3B + 3C = -27