Question

Anna is given a defined sequence with n representing the position of a term. y_(n)=3(6)ⁿ+1 Starting with n=1 what should Anna write down for the first 3 terms.

Answer 1

The first three terms of the sequence y_n = 3(6)^n+1 for n=1, 2, 3 are 19, 109, and 649.

Step-by-step explanation:

Anna is given the sequence yn = 3(6)n+1, where n represents the position of a term. To find the first three terms of the sequence starting with n=1, we need to substitute n with 1, 2, and 3 sequentially.

1. For n=1: y1 = 3(6)1+1 = 3(6)+1 = 18+1 = 19
2. For n=2: y2 = 3(6)2+1 = 3(36)+1 = 108+1 = 109
3. For n=3: y3 = 3(6)3+1 = 3(216)+1 = 648+1 = 649

Hence, the first three terms that Anna should write down for the sequence are 19, 109, and 649.