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Solve 2r²-3r-5=0 using the quadratic formula

User Andreee
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Final answer:

To solve the quadratic equation 2r² - 3r - 5 = 0 using the quadratic formula, substitute the values of a, b, and c into the formula and simplify.

Step-by-step explanation:

To solve the quadratic equation 2r² - 3r - 5 = 0 using the quadratic formula, we need to first identify the values of a, b, and c in the equation ax² + bx + c = 0.

In this case, a = 2, b = -3, and c = -5.

Substituting these values into the quadratic formula, we have:

r = (-b ± √(b² - 4ac))/(2a)

Plugging in the values, we get:

r = (-(-3) ± √((-3)² - 4(2)(-5)))/(2(2))

Simplifying further, we get:

r = (3 ± √(9 + 40))/4

r = (3 ± √49)/4

r = (3 ± 7)/4

So, the solutions are:

r = (3 + 7)/4 = 10/4 = 2.5

r = (3 - 7)/4 = -4/4 = -1

User Bengineer
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