Question

The height of a projectile launched straight up in the air is given by the function f(t) = -16t^2 + 332t + 7. Find its velocity 4.8 seconds after it is launched.

Answer 1

The velocity of the projectile 4.8 seconds after it is launched is 178.4 feet per second.

Step-by-step explanation:

To find the velocity of the projectile 4.8 seconds after it is launched, we can differentiate the given height function with respect to time to find the velocity function. The velocity function is the derivative of the height function, so the velocity function is f'(t) = -32t + 332. To find the velocity at 4.8 seconds, we substitute t = 4.8 into the velocity function:

f'(4.8) = -32(4.8) + 332 = -153.6 + 332 = 178.4. Therefore, the velocity of the projectile 4.8 seconds after it is launched is 178.4 feet per second.