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Solve using the quadratic 2v²+6v-6=0 Write your answers as integer.

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Final answer:

To solve the quadratic equation 2v²+6v-6=0, we can use the quadratic formula. The solutions are approximately v ≈ 0.732 and v ≈ -3.732.

Step-by-step explanation:

To solve the quadratic equation 2v²+6v-6=0, we can use the quadratic formula. The quadratic formula states that for an equation of the form ax²+bx+c=0, the solutions for x are given by:

x = (-b ± √(b²-4ac))/(2a)

In our equation, a=2, b=6, and c=-6. Plugging these values into the quadratic formula, we get:

x = (-6 ± √(6²-4(2)(-6)))/(2(2))

Simplifying further, we have:

x = (-6 ± √(36+48))/(4)

x = (-6 ± √(84))/(4)

Now, let's find the two possible solutions for x by calculating the square root of 84 and solving for x using both the positive and negative square root:

x ≈ (-6 + √84)/(4) ≈ 0.732

x ≈ (-6 - √84)/(4) ≈ -3.732

Therefore, the solutions to the quadratic equation 2v²+6v-6=0 are approximately v ≈ 0.732 and v ≈ -3.732.

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