Question

A planet has a radius of 5 000 km. The acceleration of free fall of the planet is 6.05 m s-2. Determine the (i) Mass of the planet

(II) Escape velocity of the planet​

Answer 1

Step-by-step explanation:

Given:

R = 5 000 km = 5*10⁶ m

g = 6.05 m/s²

G = 6.67·10⁻¹¹ m³/(kg*c²)

______________

M - ?

V - ?

(i)

g = G·M /R²

M = g·R² / G = 6.05·(5·10⁶)² / 6.67·10⁻¹¹ ≈ 2.27·10²⁴ kg·

(ii)

V = √ (g·R) = √ (6.05·5*10⁶) ≈ 5 500 m/s = 5.5 km/s