Final answer:
To find the value of 'a' when the equation 3x²+3xy+3y³=0 is satisfied at the point (-2,-2), substitute the values of x and y into the equation and solve for a.
Step-by-step explanation:
To find the value of a when the equation 3x²+3xy+3y³=0 is satisfied at the point (-2,-2), we need to substitute the values of x and y into the equation and solve for a.
When we substitute x = -2 and y = -2 into the equation, we get:
3(-2)² + 3(-2)(-2) + 3(-2)³ = a
Simplifying this equation gives:
12 - 12 + 3(-8) = a
-12 - 24 = a
-36 = a
Therefore, the value of a is -36 when the equation is satisfied at the point (-2,-2).