23.7k views
1 vote
Find any-intercepts and test for sy y=x²-5x

User Dredozubov
by
7.3k points

1 Answer

4 votes

Final answer:

To find the x-intercepts of the equation y = x² - 5x, set y=0 and solve for x. The x-intercepts are x=0 and x=5. To test for symmetry, substitute -x for x in the equation and simplify. The graph is not symmetric about the y-axis.

Step-by-step explanation:

To find the x-intercepts of the given equation y = x² - 5x, we need to set y equal to zero and solve for x. So we have:

0 = x² - 5x

Using factoring, we can rewrite this equation as:

0 = x(x - 5)

So the x-intercepts are x = 0 and x = 5.

To test for symmetry, we can substitute -x for x in the equation and simplify. If the resulting expression is equal to the original equation, then the graph is symmetric about the y-axis. In this case, we have:

y = (-x)² - 5(-x)

Simplifying, we get:

y = x² + 5x

Since y = x² - 5x is not equal to y = x² + 5x, the graph is not symmetric about the y-axis.

User Neetu
by
7.2k points