Final answer:
To prepare a 2.316 M solution of hydrochloric acid from a 7.61 M solution, you would need to add 51.75 mL of water to 169.63 mL of the 7.61 M hydrochloric acid.
Step-by-step explanation:
To prepare a 2.316 M solution of hydrochloric acid from a 7.61 M solution, you need to dilute it with water.
In order to calculate how much water to add, you can use the formula C1V1 = C2V2, where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
Rearranging the equation, you get V1 = (C2V2)/C1.
Plugging in the values, V1 = (2.316 M * 169.63 mL) / 7.61 M
= 51.75 mL.
Therefore, you would need to add 51.75 mL of water to the 169.63 mL of 7.61 M hydrochloric acid to prepare a 2.316 M solution.