Final answer:
The amplitude of the function y = -(3/2)sin((3/2)x) is 1.5 units, and its period is 4π/3 radians or approximately 4.19 units.
Step-by-step explanation:
To find the amplitude and period of the function y = -(3/2)sin((3/2)x), we can compare the function to the standard wave function form y(x, t) = A sin(kx - wt + p). In the given function, the coefficient before the sine function, which is -3/2, represents the amplitude, but since amplitude is always a positive value, we take the absolute value, resulting in an amplitude of 3/2 or 1.5 units.
The period of sine and cosine functions is 2π divided by the coefficient of x inside the sine or cosine function. In our case, the coefficient of x is 3/2, so we calculate the period as 2π / (3/2) = 4π/3. Thus, the period of the function y = -(3/2)sin((3/2)x) is 4π/3 radians or approximately 4.19 units.