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Find the integral ∫[(x³-7)/x] dx.

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Final answer:

The integral of (x³-7)/x is found by simplifying the expression to x²-7/x and then integrating each term to get (1/3)x³ - 7 ln|x| + C, where C is the constant of integration.

Step-by-step explanation:

When finding the integral of the function (x³-7)/x, we first simplify the expression inside the integral. This can be done by dividing both terms by x which gives us x²-7/x. We then integrate each term separately.



∫ (x³-7)/x dx = ∫ x² dx - ∫ 7/x dx

The integral of x² is (1/3)x³ and the integral of 7/x is 7 ln|x|. So, the integral of the original function is:



∫ (x³-7)/x dx = (1/3)x³ - 7 ln|x| + C

where C is the constant of integration.

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