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A 1-kilogram mass is attached to a spring whose constant is 21 N/m, and the entire system is then submerged in a liquid that imparts a damping force numerically equal to 10 N·s/m.

User Semyon
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Final answer:

The question is about the forces acting on a 1-kilogram mass attached to a spring submerged in a liquid. The net force is the sum of the spring force and the damping force.

Step-by-step explanation:

In this question, we have a 1-kilogram mass attached to a spring. The spring constant is 21 N/m, and the system is submerged in a liquid that imparts a damping force of 10 N·s/m. The damping force opposes the motion of the mass, slowing it down. The spring force, on the other hand, is proportional to the displacement of the mass from equilibrium.

To calculate the net force on the mass, we need to consider both the spring force and the damping force. The net force is given by:

Net Force = -kx - bv

Where k is the spring constant, x is the displacement from equilibrium, b is the damping coefficient, and v is the velocity of the mass.

To find the equilibrium position of the mass, we set the net force equal to zero:

-21x - 10v = 0

This equation describes the motion of the mass and can be used to solve for the displacement and velocity at any time. However, without additional information about the initial conditions or the equation of motion, we cannot determine the exact values of x and v.

User Krzysztof Piszko
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