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Find the equation of the tangent line to the graph f(x)=(x²+2)(x+1) at the point (1,6). Use a graphing utility to graph the function and tangent line in the same viewing window.

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The equation of the tangent line is y = 7x -1

How to find equation of tangent line.

The equation of the tangent line to the graph f(x) = (x² + 2)(x + 1) at the point (1, 6)\), follow these steps:

Find the derivative f'(x) to find the slope of the tangent at x= 1

f(x) = (x² + 2)(x + 1)

f'(x) = (2x)(x + 1) + (x² + 2)(1)

Calculate the derivative of f(x)

When x = 1

f'(1) = (2)(2) + (3)(1)

= 4 + 3

= 7

Use the point-slope form of the equation of a line: y - y₁ = m(x - x₁), where (x₁, y₁) is the given point, and m, is the slope.

y -6 = 7(x -1)

y - 6 = 7x -7

y = 7x -7 + 6

y = 7x -1

Therefore, the equation of the tangent line is y = 7x -1

Find the equation of the tangent line to the graph f(x)=(x²+2)(x+1) at the point (1,6). Use-example-1
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