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Find the real solution (s) of the given equ (-7x-3)^(2)+4(-7x-3)+3=0

User Shobhit
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1 Answer

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Final answer:

The real solutions to the equation are x = 0 and x = -1/7.

Step-by-step explanation:

This quadratic equation can be solved using the quadratic formula. The given equation is:

(-7x-3)² + 4(-7x-3) + 3 = 0

By expanding and simplifying the equation, we get:

49x² + 42x + 9 + (-28x - 12) + 3 = 0

Combine like terms and rearrange the equation:

49x² + 14x = 0

Apply the quadratic formula:

x = (-b ± √(b² - 4ac))/(2a)

From the equation, the coefficients are:

a = 49, b = 14, c = 0

Substitute these values into the formula:

x = (-14 ± √(14² - 4*49*0))/(2*49)

Simplify further:

x = (-14 ± √(196))/(98)

x = (-14 ± 14)/(98)

x = 0 or x = -1/7

Therefore, the real solutions to the equation are x = 0 and x = -1/7.

User Klefevre
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