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Consider the equation below.

[ f(x)=8 \sin (x)+8 \cos (x), quad 0 leq x leq 2 pi ]
(a) Find the interval on which ( f ) is increasing. Find the interval on which ( f ) is decreasing.

User Elachell
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1 Answer

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Final answer:

To find the intervals on which the function (f) is increasing or decreasing, we calculate the derivative of f(x) and examine its sign. The increasing interval of f(x) is (π/4, 5π/4) and the decreasing interval is (5π/4, 9π/4).

Step-by-step explanation:

To find the intervals on which the function (f) is increasing or decreasing, we need to examine the derivative of the function. Let's start by finding the derivative of f(x):

f'(x) = 8 cos(x) - 8 sin(x)

Now, to determine where f'(x) is positive (increasing) or negative (decreasing), we need to find the values of x for which f'(x) is greater than zero or less than zero:

Increasing Interval: f'(x) > 0

8 cos(x) - 8 sin(x) > 0

cos(x) - sin(x) > 0

We can use the unit circle or trigonometric properties to find the solution, which is x ∈ (π/4, 5π/4).

Decreasing Interval: f'(x) < 0

8 cos(x) - 8 sin(x) < 0

cos(x) - sin(x) < 0

Again, using the unit circle or trigonometric properties, the solution is x ∈ (5π/4, 9π/4).

User Uliwitness
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