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Len has $25 to bowl and to buy a snack. Each game costs $4 and the snack Len wants to buy costs $3. What is the greatest number of games that Len can bowl?

User Jeevamuthu
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1 Answer

3 votes

Final answer :

The greatest number of games Len can bowl after buying the snack is 5.

Step-by-step explanation:

To solve the problem, we'll need to follow these steps:

1. Determine how much money Len will have left after purchasing the snack.
2. Use the remaining amount to calculate how many games Len can play, based on the cost per game.

Let's start:

Calculating the Remaining Money

Len has $25 in total, and the snack costs $3.

So, after buying the snack, Len will have: $25 - $3 = $22 left for bowling.

Calculating the Maximum Number of Games Len Can Play

Each game of bowling costs $4.

To find out how many full games Len can play with the remaining $22, we want to determine how many times $4 can be subtracted from $22 without going negative:

$22 divided by $4 per game equals 5 with a remainder of $2, since 22 = 4 * 5 + 2.

So, Len can pay for 5 full games of bowling with the $22 left after buying the snack. The remainder of $2 is not enough to pay for another game since a full game costs $4.

Thus, the greatest number of games Len can bowl after buying the snack is 5.

User Sukanto
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