Final answer:
To solve the given integral equation, we need to find the values of a and b. By evaluating the integrals on both sides and setting them equal to each other, we can determine the values of a and b.
Step-by-step explanation:
To solve the integral equation ∫₀π / 299 cos t/√(1+sin ² t) d t=∫ₐ ᵇ q θ d θ, we need to find the values of a and b. Let's first evaluate the integral on the left side of the equation. Using the identity cos²(t) = (1+cos(2t))/2, we have:
- ∫₀π / 299 cos t/√(1+sin ² t) d t = ∫₀π / 299 cos t/√(1+(1-cos²(t))) d t
- Using the substitution u = sin(t), we can rewrite the integral as:
- ∫₀π / 299 cos t/√(1-u²) d t = ∫₀π / 299 du/√(1-u²)
Now, let's solve the integral on the right side of the equation
∫ₐ ᵇ q θ d θ = q(θ) |ₐ ᵇ = q(b) - q(a)
By setting the integrals on both sides of the equation equal to each other, we can find the values of a and b.