Final answer:
To find the player's hang time given their vertical leap of 32 inches and the function V(T) = 48T², solve for T by dividing the vertical leap by 48 and then taking the square root. The result, rounded to the nearest tenth, is approximately 0.8 seconds.
Step-by-step explanation:
To solve for the player's hang time, given their vertical leap and the function V(T) = 48T², you first need to input the known vertical leap into the equation and solve for T. In this case, the player's vertical leap is 32 inches, so the equation would be set up as 32 = 48T². To find T, divide both sides of the equation by 48, giving T² = 32/48 or T² = 2/3. Taking the square root of both sides gives T = √(2/3), which simplifies to T ≈ 0.8165 seconds. Rounding to the nearest tenth gives us T ≈ 0.8 seconds. That's the player's hang time.