Question

Abdul went sky diving from a hot air balloon that was flying at an altitude of 4,500 meters. For 14.5seconds during his fall, he was dropping at a constant velocity of 56.0meterspersecond toward the ground. In this time, how far did he fall?

Answer 1

Abdul fell 812 meters during his 14.5-second skydiving descent, calculated by multiplying his constant velocity of 56.0 meters per second by the time of descent.

Step-by-step explanation:

Abdul's fall can be calculated using the formula: distance = velocity × time. Given that Abdul fell at a constant velocity of 56.0 meters per second for 14.5 seconds, we multiply these values to find the total distance. Therefore, distance = 56.0 m/s × 14.5 s = 812 meters.

This calculation assumes a constant velocity throughout the fall, meaning there is no acceleration or deceleration. In real-world scenarios, factors like air resistance may affect the fall, but for this simplified calculation, we consider a constant velocity.

In skydiving, understanding the physics of free fall is crucial for ensuring safety and proper parachute deployment. The initial altitude of 4,500 meters is not directly used in the calculation of the fall distance but is relevant for understanding the context of the jump.