**Identification of Elements:**
1. **Start/End:** Oval shape representing the start and end of the flowchart.
2. **Process:** Rectangle indicating a process or computation step.
3. **Input/Output:** Parallelogram representing input or output operations.
4. **Decision:** Diamond shape for decision-making points.
5. **Arrow:** Arrows connecting the elements to show the flow of the process.
**Flowchart:**
1. **Start:** Oval
2. **Input:** Rectangle (Input x, y)
3. **Process:** Rectangle (Calculate z=-x³/12-4y²+6xy+20x-2y)
4. **Output:** Parallelogram (Display z)
5. **Decision:** Diamond (Check if first-order conditions are met)
6. **Process:** Rectangle (If yes, display stationary values; if no, end)
7. **End:** Oval
**Pseudo Code:**
```
Start
Input x, y
z = -x³/12 - 4y² + 6xy + 20x - 2y
Display z
If first-order conditions are met:
Display stationary values
Else:
End
End
```
Final Answer
Stationary values are found by solving the first-order conditions.
Step-by-step explanation
To find stationary values, we need to calculate the first-order partial derivatives of the given function with respect to x and y. Setting these derivatives equal to zero and solving for x and y will provide the stationary points. Let
Setting both of these equal to zero and solving simultaneously will yield the values of x and y at the stationary points.
For example, solving
imultaneously will give the values of x and y. Once these values are found, they can be substituted back into the original function to obtain the corresponding z values at the stationary points.
In summary, the stationary values are obtained by solving the system of equations formed by setting the partial derivatives of the function equal to zero.