Final answer:
To solve the equation 6f²+2f-2=0 using the quadratic formula, rearrange the equation in the form ax²+bx+c=0. Substitute the values into the quadratic formula and simplify to find the solutions.
Step-by-step explanation:
To solve the equation 6f²+2f-2=0 using the quadratic formula, we need to rearrange the equation in the form ax²+bx+c=0. In this case, a=6, b=2, and c=-2. Substituting these values into the quadratic formula, we get:
f = (-b ± sqrt(b²-4ac))/(2a)
Plugging in the values, we have:
f = (-2 ± sqrt((2)²-4(6)(-2)))/(2(6))
Simplifying the expression further, we find two possible solutions for f:
f = (-2 ± sqrt(4+48))/12
f = (-2 ± sqrt(52))/12
Hence, the solutions for f are approximately:
f = (-2 + sqrt(52))/12
f = (-2 - sqrt(52))/12