Question

here is a line that includes the point (9,1) and has a slope of 1/9. what is its equation in slope intercept form?

Answer 1

`(\stackrel{x_1}{9}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{9} \\\\\\ \begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{9}}(x-\stackrel{x_1}{9}) \\\\\\ y-1=\cfrac{1}{9}x-1\implies {\Large \begin{array}{llll} y=\cfrac{1}{9}x \end{array}}`