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Order Esmolol 2.5 g in 250 mL 0.9% NS at 30mL/hr. Calculate the
following mg/hr

User John Ken
by
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1 Answer

7 votes

Final answer:

The dosage of Esmolol being delivered is calculated at 300 mg per hour when infused at a rate of 30 mL per hour, given a total drug volume of 2.5 grams in 250 mL of normal saline.

Step-by-step explanation:

The question asks for the calculation of the dosage of Esmolol in milligrams per hour when infused at a rate of 30mL per hour. We know that the total amount of Esmolol is 2.5 grams, which is equal to 2500 milligrams (since 1 gram = 1000 milligrams), and this is dissolved in 250 mL of 0.9% normal saline.

First, we need to determine the concentration of the Esmolol solution in mg/mL. To do this, we divide the total amount of the drug in milligrams by the total volume of the solution in milliliters:

Concentration = Total amount of drug (mg) / Total volume of solution (mL) = 2500 mg / 250 mL = 10 mg/mL.

Next, to find out how many milligrams are infused per hour, we multiply the concentration of the solution by the infusion rate (30 mL/hr):

Dosage per hour = Concentration (mg/mL) × Infusion rate (mL/hr) = 10 mg/mL × 30 mL/hr = 300 mg/hr.

Therefore, the dosage of Esmolol being administered is 300 mg per hour.

User Selast Lambou
by
8.3k points
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